8x^2+71x-192=0

Solution for 8x^2+71x-192=0 equation:

8x^2+71x-192=0

a = 8; b = 71; c = -192;
Δ = b2-4ac
Δ = 712-4·8·(-192)
Δ = 11185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(71)-\sqrt{11185}}{2*8}=\frac{-71-\sqrt{11185}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(71)+\sqrt{11185}}{2*8}=\frac{-71+\sqrt{11185}}{16}
$